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Phy 201
Your 'cq_1_02.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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The problem:
A ball starts with velocity 4 cm/sec and ends with a velocity of 10 cm/sec.
• What is your best guess about the ball's average velocity?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
4 cm/sec + 10 cm/sec = 14 cm/sec / 2 = 7 cm/sec
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• Without further information, why is this just a guess?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
This is just a guess because average velocity is the change in position divided by the change in time. All we were given was the balls velocity at 2 different points in time, the start and end. We have no clue how long (in seconds) that the ball traveled or the distance (in cm).
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• If it takes 3 seconds to get from the first velocity to the second, then what is your best guess about how far it traveled during that time?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
7 cm /sec for 3 seconds = 21 cm
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• At what average rate did its velocity change with respect to clock time during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
We are trying to find the average acceleration which is change in velocity divided by clock time.
(10 cm/sec - 4 cm/sec ) / 3 sec = 6 cm/sec / 3 sec = 2 cm/sec /sec
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&#Very good responses. Let me know if you have questions. &#