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course Phy 121
9/9 around 5:00
The problem:A ball is moving at 10 cm/s when clock time is 4 seconds, and at 40 cm/s when clock time is 9 seconds.
Sketch a v vs. t graph and represent these two events by the points (4 sec, 10 cm/s) and (9 s, 40 cm/s).
answer/question/discussion (start in the next line):
the y axis is the time and the x axis is the distance.
You have that reversed.
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Sketch a straight line segment between these points.
answer/question/discussion (start in the next line):
the line increasing at a steep rate.
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What are the rise, run and slope of this segment?
answer/question/discussion (start in the next line):
rise is 10, run is 5 and the slope is (9 s - 4 s) / (40 cm/s - 10 cm/s) = 5s / 30cm/s
=1/6 cm
you got your axes reversed, but otherwise your calculation is detailed and correct; however s / (cm/s) would be s^2 / cm, not cm.
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What is the area of the graph beneath this segment?
answer/question/discussion (start in the next line):
????? i don't know how to do this.
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Hopefully I've got the link right. See my notes, then check the link below, and in this case do resubmit. Let me know if the link isn't right.
&#See any notes I might have inserted into your document. If there are no notes, this does not mean that your solution is completely correct.
Then please compare your solutions with the expanded discussion at the link
Solution
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