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PHY 201
Your 'cq_1_05.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_05.1_labelMessages **
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The problem:
A ball accelerates at 8 cm/s^2 for 3 seconds, starting with velocity 12 cm/s.
What will be its velocity after the 3 seconds has elapsed?
answer/question/discussion: ->->->->->->->->->->->-> :
For each second that passes, an additional 8cm/s is added to the v_0. Since v_0 = 12 cm/s, after one second the ball is traveling at (12cm/s +8cm/s) = 20cm/s. After the second second passes, the ball travels at 28cm/s and finishes the third second at 36cm/s.
Another way of looking at this is to mulitply the aAve by 3 (`ds), 8cm/s^2 * 3sec = 24cm/s, and add this to the v_0 of 12cm/s, 24cm/s + 12cm/s = 36cm/s.
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Assuming that acceleration is constant, what will be its average velocity during this interval?
answer/question/discussion: ->->->->->->->->->->->-> :
vAve= (12cm/s + 36cm/s) / 2 = 48cm/s / 2 = 24cm/s.
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How far will it travel during this interval?
answer/question/discussion: ->->->->->->->->->->->-> :
Area= vAve * `dt = 24cm/s * 3sec = 72cm. This is the same as displacement.
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&#Very good responses. Let me know if you have questions. &#