cq_1_051

Your 'cq_1_05.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

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The problem:

A ball accelerates at 8 cm/s^2 for 3 seconds, starting with velocity 12 cm/s.

What will be its velocity after the 3 seconds has elapsed?

36cm/s

vf = a`dt + v0 = (8cm/s)(3s) + 12 = 36cm/s

Assuming that acceleration is constant, what will be its average velocity during this interval?

24cm/s

vAve = v0+vf/2 = 12cm/s + 36cm/s / 2 = 24cm/s

How far will it travel during this interval?

72cm

I solved for the equation `ds = vAve`dt = (24)(3) = 72cm.

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20 min.

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Please respond relative to goal of C.

&#Your work looks very good. Let me know if you have any questions. &#