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The problem:
A ball accelerates at 8 cm/s^2 for 3 seconds, starting with velocity 12 cm/s.
What will be its velocity after the 3 seconds has elapsed?
36cm/s
vf = a`dt + v0 = (8cm/s)(3s) + 12 = 36cm/s
Assuming that acceleration is constant, what will be its average velocity during this interval?
24cm/s
vAve = v0+vf/2 = 12cm/s + 36cm/s / 2 = 24cm/s
How far will it travel during this interval?
72cm
I solved for the equation `ds = vAve`dt = (24)(3) = 72cm.
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20 min.
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Please respond relative to goal of C.
&#Your work looks very good. Let me know if you have any questions. &#