cq_1_051

Phy 121

Your 'cq_1_05.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

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The problem:

A ball accelerates at 8 cm/s^2 for 3 seconds, starting with velocity 12 cm/s.

• What will be its velocity after the 3 seconds has elapsed?

The velocity after 3 seconds should be 96 cm/s. The formula would be v = v0 + at. The velocity would be what we are looking for and the v0 would be zero and the (at) would be acceleration rate times the starting velocity.

You appear to have confused the identities of the given quantities.

You are given the values of three of the quantities.

Which value do you think represents a velocity, and is this an initial, final, average velocity or a change in velocity?

Which value do you think represents the acceleration?

Which value do you think represents the time interval?

How would this change your answers to this question and the subsequent questions?

• Assuming that acceleration is constant, what will be its average velocity during this interval?

The average velocity during interval will be 10 cm/s. The way that we get this would be to take the initial velocity + constant velocity divided by 2. In this case, we take 12 cm/s + 8 cm^2 / 2, which comes out to 10 cm/ s for the interval.

• How far will it travel during this interval?

t = v-v0 / a. So in this instance, the time is 8 cm/s^2 – 12 cm / 10 which results in -0.4 seconds.

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It took me about 20-25 minutes to complete this.

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