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course Mth 151

??????~???p??assignment #029029. `query 29

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College Algebra

12-14-2007

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22:35:06

7.3.18 (1/3) / 6 = 1/18. Is this ratio equation valid or not and how did you determine your answer?

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RESPONSE -->

note: mult both sides by 6*18

6*18*(1/3)/ 6=6*18*(1/18)

confidence assessment: 1

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22:37:07

7.3.20 z/8 = 49/56. Solve this proportionality for z.

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RESPONSE -->

8*56*z/8=8*56*49/56

56*z=8*49

z=8*49/56

z=7

confidence assessment: 2

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22:40:43

7.3.42 8 oz .45; 16 oz. .49; 50 oz. 1.59`sb Which is the best value per unit for green beans and how did you obtain your result?

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RESPONSE -->

45c/8oz=5.63 c/oz

49 c/16oz=3.06 c/oz

159 c/50oz=3.18c/oz

c=cents

oz=ounce

note 16oz for .49 cents is the best value

confidence assessment: 3

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22:44:29

7.3.45 triangles 4/3, 2, x; 4, 6, 3. What is the value of x and how did you use an equation to find it?

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RESPONSE -->

4/3 corres. to 4, and 2 corres. to 6, and x corres. to 3.

side 1: 4/3 /4

side 2: 2/6

side 3: x/3

x/3=2/6 x=1

x/3=4/3 / 4

confidence assessment: 2

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22:47:25

If z = 9 when x = 2/3 and z varies inversely as x, find z when x = 5/4. Show how you set up and used an equation of variation to solve this problem.

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RESPONSE -->

9=k/ 2/3

2/3 * 9= k

k=6

z=6/x x=5/4

z= 6/ 5/4 =24 /5= 4.8

z=kx^2

z=k/x^2

z=kx

confidence assessment: 1

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22:51:04

7.3.72. Illumination is inversely proportional to the square of the distance from the source. Illumination at 4 ft is 75 foot-candles. What is illumination at 9 feet?

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RESPONSE -->

1=75

r=4

75=k/4^2

k=75*4^2=75*16=1200

1=1200/r62

1=1200/ 9^2 =1200 /81=14.8

the illumination is about 14.8

confidence assessment: 2

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22:53:28

7.3.66 length inv prop width; L=27 if w=10; w = 18. L = ?

Explain how you set up and used a variation equation to obtain the length as a function of width, giving your value of k. Then explain how you used your equation to find the length for width 18

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RESPONSE -->

L=k/w

L=27

w=10

27=k/10

k=27* 10=270

L=270/w (w=18)

L=270/18=15

confidence assessment: 1

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