PHY 201
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Seed 12.1
Masses of 5 kg and 6 kg are suspended from opposite sides of a light frictionless pulley and are released.
What will be the net force on the 2-mass system and what will be the magnitude and direction of its acceleration?
answer/question/discussion:
If we think of the direction of the 6 kg weight as positive and the 5 kg as negative, then the net force would be:
Fnet = m*a
Fnet = 5*-9.8 + 6*9.8
Fnet = 1*9.8 = 9.8 Newtons
(this is 9.8 m/s/s in the descending direction of the 6 kg mass)
If you give the system a push so that at the instant of release the 5 kg object is descending at 1.8 meters / second, what will be the speed and direction of
motion of the 5 kg mass 1 second later?
The object would be traveling 1.8 m/s with an acceleration of -9.8 m/s/s
There is a net force of 9.8 Newtons, acting on a system which contains masses of 5 kg and 6 kg.
What is the net force on the system?
What is the mass of the system?
What therefore is its acceleration?
a = 'dv/'dt
-9.8 = 'dv/1
'dv = -9.8 m/s
1.8-9.8 = -8 m/s
This means the 5 kg mass is ascending at 8 m/s
answer/question/discussion:
During the first second, are the velocity and acceleration of the system in the same direction or in opposite directions, and does the system slow down or
speed up?
answer/question/discussion:
The acceleration is really like a deceleration changing the direction of the 5 kg mass, so they're in opposite directions.
The system begins speeding up after it reaches a speed of 0 m/s. It then begins traveling in the direction of the 6 kg object and speeds up over the se\cond.
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30 mins
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The acceleration of this system is not 9.8 m/s^2.
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