PHY 201
Your 'cq_1_24.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A steel ball of mass 60 grams, moving at 80 cm / sec, collides with a stationary marble of mass 20 grams. As a result of the collision the steel ball slows
to 50 cm / sec and the marble speeds up to 70 cm / sec.
Is the total momentum of the system after collision the same as the total momentum before?
answer/question/discussion:
m1v1 + m2v2 = m1v1F + m2v2F
60(80) + 0 = 60(60) + 70(20)
4800 = 3600 + 1400
So no, the difference in momentum is 200 meaning the collision gained 200 g cm/s momentum which seems impossible
What would the marble velocity have to be in order to exactly conserve momentum, assuming the steel ball's velocities to be accurate?
answer/question/discussion:
4800 = 3600 + 70x
1200 = 70x
x = 17.14 cm/s
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15 min
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&#Good responses. See my notes and let me know if you have questions. &#