PHY 201
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A steel ball of mass 110 grams moves with a speed of 30 cm / second around a circle of radius 20 cm.
What are the magnitude and direction of the centripetal acceleration of the ball?
answer/question/discussion:
The magnitude is v^2/r = 900/20 = 45 cm/s/s or .45 m/s/s and I believe I remember reading the acceleration is always directed towards the center of the
circle
That is so in this case, and any time an object moves along a circle with constant velocity.
Any time an object moves along a circle, whether velocity is constant or not, centripetal acceleration is v^2 / r and is toward the center (that's what 'centripetal' means); since the direction of motion along the circle is always perpendicular to its velocity, the centripetal acceleration is perpendicular to the velocity.
If the object is changing speed there is also a component of acceleration in the direction of motion.
What is the magnitude and direction of the centripetal force required to keep it moving around this circle?
answer/question/discussion:
Fcent = .11(.45) = .0495 Newtons
I believe it is also directed towards the center of the circle
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15 min
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&#Very good responses. Let me know if you have questions. &#