assignment 16 query

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course mth151

11/23 around 7:50

If your solution to stated problem does not match the given solution, you should self-critique per instructions at

http://vhcc2.vhcc.edu/dsmith/geninfo/labrynth_created_fall_05/levl1_22/levl2_81/file3_259.htm

Your solution, attempt at solution. If you are unable to attempt a solution, give a phrase-by-phrase interpretation

of the problem along with a statement of what you do or do not understand about it. This response should be given,

based on the work you did in completing the assignment, before you look at the given solution.

016. `query 16

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Question: `qquery 3.5.5 all dogs love to bury bones. Archie doesn't. Therefore Archie isn't a dog .

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Your solution:

the arguement is valid. this arguement is saying that all dogs love to bury bones. if archie does not meet that

requirement then according to the arguement he cannot be a dog. the argument does not contradict itself so is

therefor valid

confidence rating #$&*:3

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Given Solution:

`a** You would put all dogs in a circle, and this circle would be inside another circle consisting of all things

that love to bury bones. Archie is outside this bone-burying circle and since this circle contains all dogs Archie

isn't a dog.

This makes the argument valid.

The x for Archie has to go outside the outer circle, so it has to be outside the inner circle. Thus the x can't be

in the inner circle, and Archie therefore can't be a dog. The conclusion can't be contradicted.

COMMON ERROR WITH INSTRUCTOR RESPONSE: I put 'all dogs like to bury bones' in one circle and 'archie likes to bury

bones' in another.

INSTRUCTOR RESPONSE:

You don't want to use a single circle to represent a compound statement. 'All dogs like to bury bones' and 'Archie

likes to bury bones' are compound statements.

SIMILAR ERROR: in one circle ,I put all dogs love to bury bones, inthe other circle I put Archie, so I knew that

Archie wasn't a dog, so the statement is valid .

INSTRUCTOR COMMENT: See previous comment.

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Self-critique (if necessary):ok

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Self-critique Rating:ok

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Question: `qquery 3.5.20 all chickens have a beak. All hens are chickens. Therefore all hens have beaks.

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Your solution:

the arguement is valid. to prove this in forms of the circles you would first draw a circle for things with beaks.

then you would draw the circle for the chickens inside of the beaks circle since all chickens have a beak. since all

hens are chicken the hen circle would have to be inside of the chicken circle. since the hen circle is in the

chicken circle which is in the beak circle then you can say that all hens have beaks

confidence rating #$&*:3

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Given Solution:

`a** You need to show the relationship between chickens and things with breaks.

You would make a circle for everything with a beak and another circle for chickens.

Since all chickens have beaks the chicken circle has to be inside the 'beaked' circle.

Then you have hens. They are all chickens so the hen circle is inside the chicken circle.

Since the chicken circle is already inside the beaked circle the hen circle (inside the chicken circle) is also

inside the beaked circle, and you conclude that all hens have beaks.

COMMON ERROR WITH INSTRUCTOR COMMENT:

In the outer circle, I put chickens with beaks. Inside that circle, I made another circle for hens are chickens.

INSTRUCTOR COMMENT: 'hens are chickens' is a statement, not a thing. The circles have to be defined by things.

SIMILAR ERROR WITH COMMENT: Two circles: large circle of hens are chickens and a smalled circle within of hens

have beaks. Valid

INSTRUCTOR COMMENT: You don't put propositions into circle (e.g., 'hens are chickens' isn't a circle). You put

sets of things into circles (e.g., a circle for hens and a circle for chickens, with the hens circle inside the

chickens circle). **

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Self-critique (if necessary):ok

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Self-critique Rating:ok

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Question: `qWhen the diagram is drawn according to the premises, is it or is it not possible for the diagram to be

drawn so that it contradicts the conclusion? If it is possible describe how.

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Your solution:

it is not possible to follow the premises and contradict the conclusion. the hens must be in the chickens circle and

the chickens (which include the hens) must be in the beaks circle for you to correctly follow the premises

confidence rating #$&*:3

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Given Solution:

`a** The circle for hens must be inside the circle for chickens, which is inside the circle for beaked creatures.

Therefore the circle for hens must be inside the circle for beaked creatures. No other way to draw it consistent

with the conditions. **

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Self-critique (if necessary):ok

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Self-critique Rating:ok

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Question: `qWhen the diagram is drawn according to the premises, is it or is it not possible for the diagram to be

drawn so that it contradicts the conclusion? If it is possible describe how.

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Your solution:

it is not possible to follow the premises and contradict the conclusion. the hens must be in the chickens circle and

the chickens (which include the hens) must be in the beaks circle for you to correctly follow the premises

confidence rating #$&*:3

^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

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Given Solution:

`a** The circle for hens must be inside the circle for chickens, which is inside the circle for beaked creatures.

Therefore the circle for hens must be inside the circle for beaked creatures. No other way to draw it consistent

with the conditions. **

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Self-critique (if necessary):ok

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Self-critique Rating:ok

#*&!

&#Good responses. Let me know if you have questions. &#