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course phy241
9/16 7:54PM
If the velocity of the object changes from 5 cm / sec to 15 cm / sec in 9 seconds, then at what average rate is the velocity changing?15cm/s - 5cm/s = 10cm/s Now divide this by the amount of second passed
10cm/s/9s = 1.11cm/s/s = 1.11cm/s^2
A ball rolling from rest down a constant incline requires 3.9 seconds to roll the 49 centimeter length of the incline.
What is its average velocity?
vAve = `ds / `dt = 49cm / 3.9s = 12.56cm/s
An object which accelerates uniformly from rest will attain a final velocity which is double its average velocity.
What therefore is the final velocity of this ball?
If the Final velocity of an object accelerating uniformly is double the average velocity, then its final velocity must be 12.56 * 2 = 25.12 cm/s
What average rate is the velocity of the ball therefore changing?
25.12cm/s / 3.9s = 6.44m/s^2
An automobile accelerates uniformly down a constant incline, starting from rest. It requires 13 seconds to cover a distance of 110 meters. At what average rate is the velocity of the automobile therefore changing?
vAve = `ds / `dt = 110m / 13s = 8.46m/s * 2 = 16.9m/s => Final velocity.
Average rate of velocity is calculated by : 16.9m/s/13s = 1.3m/s^2
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