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Phy 241
Your 'cq_1_03.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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cq_1_031
#$&*
Phy 241
Your 'cq_1_03.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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The problem:
A ball starts with velocity 0 and accelerates uniformly down a ramp of length 30 cm, covering the distance in 5 seconds.
What is its average velocity?
answer/question/discussion: ->->->->->->->->->->->-> : ->->->->->->->->->->->-> (start in the next line):
(30 - 0)/(5 - 0) = 30/5 = 6cm/s
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If the acceleration of the ball is uniform then its average velocity is equal to the average of its initial and final velocities.
You know its average velocity, and you know the initial velocity is zero.
What therefore must be the final velocity?
answer/question/discussion: ->->->->->->->->->->->-> : ->->->->->->->->->->->-> (start in the next line):
if average velocity is = to the average of its initial and final velocities, then we must know that its final velocity is 6cm/s.
@& If final vel was 6 cm/s, then starting from rest the average vel would be 3 cm/s.
However ave vel is 6 cm/s.
So final vel is not 6 cm/s, and later, the accel is not 1.2 cm/s^2.
This should be easy to fix.*@
&&&& Oh! Yes! I think I might of misunderstood the question.. The correct answer should be twice the average vel (6cm/s), therefor final velocity;
2(6cm/s) = 12cm/s
And later, acceleration will equal;
12cm/s / 5s = 2.4cm/s^2
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By how much did its velocity therefore change?
answer/question/discussion: ->->->->->->->->->->->-> : ->->->->->->->->->->->-> (start in the next line):
Velocity changed by 6cm/s
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@& Velocity changed from 0 to 12 cm/s, a change of 12 cm/s.*@
At what average rate did its velocity change with respect to clock time?
answer/question/discussion: ->->->->->->->->->->->-> : ->->->->->->->->->->->-> (start in the next line):
6cm/s/3s = 1.2cm/s^2
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@& This is not correct.
You don't say how you got the 6 cm/s^2.*@
What would a graph of its velocity vs. clock time look like? Give the best description you can.
answer/question/discussion: ->->->->->->->->->->->-> : ->->->->->->->->->->->-> (start in the next line):
The graph would be increasing to the right, starting at the origin (0,0)
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*#&!*#&!
@& You could give the slope, and you know at least two other points on the graph.*@
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&#Please see my notes and, unless my notes indicate that revision is optional, submit a copy of this document with revisions and/or questions, and mark your insertions with &&&& (please mark each insertion at the beginning and at the end).
Be sure to include the entire document, including my notes.
If my notes indicate that revision is optional, use your own judgement as to whether a revision will benefit you. &#
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