course PHY 121 7/1 8:30p What are the acceleration and final velocity of an object whose average velocity, accelerating uniformly from rest for 7.9 seconds, is 59 cm/s? How far does the object travel during the 7.9 seconds? Since the object accelerates from rest, initial velocity is 0. We know the average velocity is 59 cm/s, so the final velocity has to be double that, since initial is 0 the final must be 2 times the average, which when added to zero and divided by 2 will give 59. Therefore the final velocity is 118 cm/s. Acceleration is the change in velocity/change in time, which is 118cm/s /7.9s = 14.9367 cm/s^2. 59cm/s * 7.9s gives the distance traveled of 466.1 cm.