course PHY 121
7/1 8:45p
How far does an object travel and what is its acceleration if its velocity increases at a uniform rate from 3 m/s to 22 m/s in 12 seconds?Explain the meaning of the slope and area of the velocity vs. time for this object during this time interval.
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The object's acceleration is the change in velocity / change in time giving 19m/s / 12s, which is 1.583 m/s/s.
The distance the object travels is computed by taking the average velocity, which is 12.5m/s * 12s = 150m. This is the area under the trapezoid of the velocity vs. time graph.
This looks very good. Let me know if you have any questions.