RandomProbsWeek2Quiz2

course PHY 121

6/7 1a

Reason out the quantities v0, vf, v, vAve, a, s and t: If an object’s velocity changes at a uniform rate from 11 cm/s to 15 cm/s as it travels 104 cm, then what is the average acceleration of the object?Using the equations which govern uniformly accelerated motion determine vf, v0, a, s and t for an object which accelerates through a distance of 104 cm, starting from velocity 11 cm/s and accelerating at .5 cm/s/s.

v0 + vf / 2 = 11cm/s + 15cm/s / 2 = 26cm/s / 2 = 13 cm/s vAve.

`ds = vAve * `dt and solve for `dt.

104cm = 13cm/s * `dt, `dt = 104cm / 13cm/s = `dt = 8s.

We now have the time interval `dt and the change in velocity `dv, so the formula for the avg. acceleration is `dv / `dt = 4cm/s / 8s = 0.5 cm/s/s.

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&#Very good responses. Let me know if you have questions. &#