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A ball starts with velocity 0 and accelerates down a ramp of length 30 cm, covering the distance in 5 seconds.
What is its average velocity?
d=rt
30=r(5)
r=6 cm/sec
If the acceleration of the ball is uniform then its average velocity is equal to the average of its initial and final velocities.
Also, if the acceleration is uniform, the final velocity will be twice the average velocity. So Vf will be 12 cm/sec.
Vave= (vf +vo)/2=12+0)/2=6 cm/sec
You know its average velocity, and you know the initial velocity is zero. What therefore must be the final velocity?
If the acceleration is uniform, the final velocity will be twice the average velocity. So Vf will be 12 cm/sec.
By how much did its velocity therefore change?
It changed by 12 cm/sec
Vf-Vo
At what average rate did its velocity change with respect to clock time?
(vf-Vo)/(Tf-To)=12cm/sec/5 sec=12/5=2.4
2.4 cm/s^2.
What would a graph of its velocity vs. clock time look like? Give the best description you can.
As the time increasees, velcoity will increase at an increasing rate. It will be somewhat expoential looking.
If acceleration is uniform, the graph of v vs. t is a straight line. The slope of this line is the acceleration.
The graph of s vs. t has slopes that represent velocities, so this graph is increasing at an increasing rate.
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10 min
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&#Good responses. See my notes and let me know if you have questions. &#