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Phy 201
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** CQ_1_05.1_labelMessages **
5.1 Has submit work form
The problem:
A ball accelerates at 8 cm/s^2 for 3 seconds, starting with velocity 12 cm/s.
What will be its velocity after the 3 seconds has elapsed?
answer/question/discussion: ->->->->->->->->->->->-> :
Since the ball is accelerating at 8cm/s^2, using the vf equation we can solve for the ball’s final velocity:
vf = vi + a * `dt
vf = 12cm/s + 8cm/s^2 * 3s
vf = 36cm/s
Velocity is represented by units of position divided by units of time, so the answer is in cm/s.
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Assuming that acceleration is constant, what will be its average velocity during this interval?
answer/question/discussion: ->->->->->->->->->->->-> :
To find the balls average velocity, we can average the vf and vi since acceleration is constant:
(vf + vi) / 2
(36cm/s + 12cm/s) / 2 = 24m/s
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How far will it travel during this interval?
answer/question/discussion: ->->->->->->->->->->->-> :
To find the change in position we can rearrange the vAve equation:
vAve= delta s / delta t
delta s = vAve * delta t
delta s = 24 cm/s * 3s
delta s = 72cm
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&#Very good responses. Let me know if you have questions. &#