course Mth 173 ????j?????·???????y·assignment #001001. Depth vs. Clock Time and Rate of Depth Change
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00:42:45 `qNote that there are four questions in this assignment. `q001. If your stocks are worth $5000 in mid-March, $5300 in mid-July and $5500 in mid-December, during which period, March-July or July-December was your money growing faster?
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RESPONSE --> well basically all i could figure to do is to add mid march and mid july and then add mid july and mid december and so the answer i would have to say would be july-december, thats when it would have most profit confidence assessment: 1
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00:46:32 The first period (4 months) was shorter than the second (5 months), and the value changed by more during the shorter first period (increase of $300) than during the longer second perios (increase of $200). A greater increase in a shorter period implies a greater rate of change. So the rate was greater during the first period.
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RESPONSE --> I thought thats what it was, i second guessed myself self critique assessment:
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00:48:27 `q002. What were the precise average rates of change during these two periods?
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RESPONSE --> 75 a month which i would guess is going to be the average rate and the next period is 50 confidence assessment: 0
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00:49:30 From mid-March thru mid-July is 4 months. A change of $300 in four months gives an average rate of change of $300 / (4 months) = $75/month. From mid-July through mid-December is 5 months, during which the value changes by $200, giving an average rate of $200 / (5 months) = $40 / month. Thus the rate was greater during the first period than during the second.
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RESPONSE --> so i thought it was the only way to do it but i just figured since the last one was wrong i got it wrong. self critique assessment: 2
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01:07:21 `q003. If the water in a uniform cylinder is leaking from a hole in the bottom, and if the water depths at clock times t = 10, 40 and 90 seconds are respectively 80 cm, 40 cm and 20 cm, is the depth of the water changing more quickly or less quickly, on the average, between t = 10 sec and t = 40 sec, or between t = 40 sec and t = 90 sec?
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RESPONSE --> i am going to say that first i have to 80 cm in 10 sec which 80-40 cm in 40 is 40 cm and the other would only be 20 so the answer is 10 sec and 40 sec confidence assessment: 1
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01:09:08 Between clock times t = 10 sec and t = 40 sec the depth changes by -40 cm, from 80 cm to 40 cm, in 30 seconds. The average rate is therefore -40 cm / (30 sec) = -1.33 cm/s. Between t = 40 sec and t = 90 sec the change is -20 cm and the time interval is 50 sec so the average rate of change is -20 cm/ 50 sec = -.4 cm/s, approx. The depth is changing more quickly during the first time interval.
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RESPONSE --> i didnt have the exact way to do it down but i understood it now that i needed to divide the deth by time and get the answer and so i still got the right answer self critique assessment: 1
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01:18:20 `q004. How are the two preceding questions actually different versions of the same question? How it is the mathematical reasoning the same in both cases?
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RESPONSE --> well you had to do them both different, one was simple math and the other took a little more involvement, and they are the same because you were trying to find the average rate in both of them confidence assessment: 1
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