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PHY 201
Your 'cq_1_04.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_04.1_labelMessages **
The problem:
A ball is moving at 10 cm/s when clock time is 4 seconds, and at 40 cm/s when clock time is 9 seconds.
•Sketch a v vs. t graph and represent these two events by the points (4 sec, 10 cm/s) and (9 s, 40 cm/s).
•Sketch a straight line segment between these points.
•What are the rise, run and slope of this segment?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The rise is from 10 cm/s to 40 cm/s, which is a rise of (40 cm/s - 10 cm/s) = 30 cm/s.
Run = 5s
Slope= rise / run = (30 cm/s) / (5 s) = 6 cm/s^2.
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•What is the area of the graph beneath this segment?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The region beneath this segment forms a trapezoid.
The area of the trapezoid is equal to average altitude * width = 25 cm/s * 5 s = 125 cm.
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&#Very good responses. Let me know if you have questions. &#