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PHY 201
Your 'cq_1_10.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_10.1_labelMessages **
pendulum requires 2 seconds to complete a cycle, which consists of a complete back-and-forth oscillation (extreme point to equilibrium to opposite extreme point back to equilibrium and finally to the original extreme point). As long as the amplitude of the motion (the amplitude is the distance from the equilibrium position to the extreme point) is small compared to the length of the pendulum, the time required for a cycle is independent of the amplitude.
•How long does it take to get from one extreme point to the other, how long from an extreme point to equilibrium, and how long to go from extreme point to equilibrium to opposite extreme point and back to equilibrium?
1/4-cycle time is 1/4 * 2 sec = 1/2 sec or .5 sec
To get from one extreme point to the other requires two quarter-cycles, 2 * .5 second = 1 second
•To get from extreme to opposite extreme and back to equilibrium takes another 1/4 cycle, a total of three quarter-cycles, which requires 3 * .5 second = 1.5 second.
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•What reasonable assumption did you make to arrive at your answers?
My assumption is that the pendulum is traveling at the same speed throughout the cycle.
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