cq_1_181

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PHY 201

Your 'cq_1_18.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

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A child in a slowly moving car tosses a ball upward. It rises to a point below the roof of the car and falls back down, at which point the child catches it. During this time the car neither speeds up nor slows down, and does not change direction.

•What force(s) act on the ball between the instant of its release and the instant at which it is caught? You can ignore air resistance.

answer/question/discussion: ->->->->->->->->->->->-> :

Gravity and the weight of the ball.

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•What happens to the speed of the ball between release and catch? Describe in some detail; a graph of speed vs. clock time would also be appropriate.

answer/question/discussion: ->->->->->->->->->->->-> :

The ball slows as it rises, then speeds up as it falls.

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•Describe the path of the ball as it would be observed by someone standing along the side of the road.

answer/question/discussion: ->->->->->->->->->->->-> :

The ball travels forward at constant speed as it rises then falls

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•How would the path differ if the child was coasting along on a bicycle? What if the kid didn't bother to catch the ball? (You know nothing about what happens after the ball makes contact with the ground, so there's no point in addressing anything that might happen after that point).

answer/question/discussion: ->->->->->->->->->->->-> :

The ball would take the same path, even if the child didn’t catch the ball.

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•What if the child drops the ball from the (inside) roof of the car to the floor? For the interval between roof and floor, how will the speed of the ball change? What will be the acceleration of the ball? (You know nothing about what happens after the ball makes contact with the floor, so there's no point in addressing anything that might happen after that point).

answer/question/discussion: ->->->->->->->->->->->-> :

The velocity of the ball would increase with the acceleration of gravity, which is 9.8 m/s^2, and would continue to increase with respect to clock time until it reached the floor where for the purpose of this problem motion would cease.

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•What if the child holds the ball out of an open window and drops it. If the ball is dense (e.g., a steel ball) and the car isn't moving very fast, air resistance will have little effect. Describe the motion of the ball as seen by the child. Describe the motion of the ball as seen by an observer by the side of the road. (You know nothing about what happens after the ball makes contact with the ground, so there's no point in addressing anything that might happen after that point).

answer/question/discussion: ->->->->->->->->->->->-> :

The child would see the ball drop straight down. From an observer by the side of the road, the ball would be seen as dropping straight down with no motion horizontally.

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15 min

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A child in a car tosses a ball upward so that after release it requires 1/2 second to rise and fall back into the child's hand at the same height from which it was released. The car is traveling at a constant speed of 10 meters / second in the horizontal direction.

•Between release and catch, how far did the ball travel in the horizontal direction?

answer/question/discussion: ->->->->->->->->->->->-> :

The ball continues to travel at 10 m/s in the horizontal direction and the ball moves `ds = vAve * `dt = 10 m/s * .5 s = 5 m in that direction within .5 sec.

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•As observed by a passenger in the car, what was the path of the ball from its release until the instant it was caught?

answer/question/discussion: ->->->->->->->->->->->-> :

The path will look as if it is curved.

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•Sketch the path of the ball as observed by a line of people standing along the side of the road. Describe your sketch. What was shape of the path of the ball?

answer/question/discussion: ->->->->->->->->->->->-> :

curved upward

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•How fast was the ball moving in the vertical direction at the instant of release? At that instant, what is its velocity as observed by a line of people standing along the side of the road?

answer/question/discussion: ->->->->->->->->->->->-> :

-9.8 m/s^2 * .5 s = -4.9 m/s

initial vertical velocity is 2.45 m/s

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•How high did the ball rise above its point of release before it began to fall back down?

answer/question/discussion: ->->->->->->->->->->->-> :

Displacement is vAve * `dt = 1.23 m/s * .25 s = .31 m

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20 min

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