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PHY 201
Your 'cq_1_25.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_25.1_labelMessages.txt **
A steel ball of mass 110 grams moves with a speed of 30 cm / second around a circle of radius 20 cm.
•What are the magnitude and direction of the centripetal acceleration of the ball?
answer/question/discussion: ->->->->->->->->->->->-> :
a = v^2 / r
•a = (30 cm/s)^2 / 20cm = 45 cm/s^2
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•What is the magnitude and direction of the centripetal force required to keep it moving around this circle?
answer/question/discussion: ->->->->->->->->->->->-> :
F_cent = m * a_Cent = .110kg * .45 m/s^2 = 49.5 kg * m/ s^2 = 49.5 N
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That would be .0495 N.
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20 min. (I had to look up formulas)
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&#This looks good. See my notes. Let me know if you have any questions. &#