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Phy 231
Your 'cq_1_02.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_02.1_labelMessages.txt **
The problem:
A ball starts with velocity 4 cm/sec and ends with a velocity of 10 cm/sec.
• What is your best guess about the ball's average velocity?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
Average velocity is the change in postion/change in clock time, so on this where there is no clock time would you simply add the two up and divide by 2? If that is correct, the average would be 7cm/sec.
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• Without further information, why is this just a guess?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
Im not sure if that was correct, but I wouldn’t know what to plug in the equation for vAve for the ‘dt(change in clock time) because it was not given.
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• If it takes 3 seconds to get from the first velocity to the second, then what is your best guess about how far it traveled during that time?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
If it takes 3 seconds to get from 1 velosity to the second then vAve = 6 ‘dt=3 so you would set up the equation for ‘ds and solve. vAve (‘dt) =’ds so (6)(3) = 18m.
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Your previous average velocity was 7 cm/s , which would give you a 21 cm displacement.
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• At what average rate did its velocity change with respect to clock time during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The average rate was 3m/sec.
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3 m/s is not an average rate of change of velocity.
I believe your only error is with the units, but so that I can tell what you have done and advise you properly you need to at least briefly show the calculation you did to get this result.
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&#Good work. See my notes and let me know if you have questions. &#