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Phy 231
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A pendulum requires 2 seconds to complete a cycle, which consists of a complete back-and-forth oscillation (extreme point to equilibrium to opposite extreme point back to equilibrium and finally to the original extreme point). As long as the amplitude of the motion (the amplitude is the distance from the equilibrium position to the extreme point) is small compared to the length of the pendulum, the time required for a cycle is independent of the amplitude.
• How long does it take to get from one extreme point to the other, how long from an extreme point to equilibrium, and how long to go from extreme point to equilibrium to opposite extreme point and back to equilibrium?
It takes 2 seconds to get from one extreme to another, .66 seconds to go from 1 extreme point to equilibrium, and .66 seconds to get from the opposite extreme point back to equilibrium.
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• What reasonable assumption did you make to arrive at your answers?
I simply took the 2 seconds and divided it into 3 parts because that is what the cycle consist of.
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If a pendulum starts at an extreme point and returns to that point, then in order, what extreme and equilibrium points does it pass?
Clearly the first point it passes is the equilibrium point. So you would list the first two points, starting with the originial extreme point, as
ex, eq
Complete this list, continuing until you have returned to the original equilibrium point.
What is your listing?
Into how many intervals does your listing divide the cycle?
How does your analysis affect your answers to the original questions?
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