Phy 201
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The problem:
A graph is constructed representing velocity vs. clock time for the interval between clock times t = 5 seconds and t = 13 seconds. The graph consists of a straight line from the point (5 sec, 16 cm/s) to the point (13 sec, 40 cm/s).
• What is the clock time at the midpoint of this interval?
answer/question/discussion: ->->->->->->->->->->->-> : 6 seconds 13-5 divided by 2
• What is the velocity at the midpoint of this interval?
answer/question/discussion: ->->->->->->->->->->->-> : 28 cm/s 40cm/s plus 15cm/s divided by 2
• How far do you think the object travels during this interval? 208cm ‘dt = 28 times 8.
answer/question/discussion: ->->->->->->->->->->->-> :
• By how much does the clock time change during this interval?
answer/question/discussion: ->->->->->->->->->->->-> : 8 seconds
• By how much does velocity change during this interval?
answer/question/discussion: ->->->->->->->->->->->-> : 24 cm/s
• What is the average rate of change of velocity with respect to clock time on this interval?
answer/question/discussion: ->->->->->->->->->->->-> : 3 cm/s/s (40-16)/(13-5)
• What is the rise of the graph between these points?
answer/question/discussion: ->->->->->->->->->->->-> : 24 cm/s (40-16)
• What is the run of the graph between these points?
answer/question/discussion: ->->->->->->->->->->->-> : 8 s (13-5)
• What is the slope of the graph between these points?
answer/question/discussion: ->->->->->->->->->->->-> : 3 cm/s/s (40-16)/(13-5)
• What does the slope of the graph tell you about the motion of the object during this interval?
answer/question/discussion: ->->->->->->->->->->->-> : The average velocity changes at a rate of 3cm/s/s.
• What is the average rate of change of the object's velocity with respect to clock time during this interval?
answer/question/discussion: ->->->->->->->->->->->-> : 3cm/s/s
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25 minutes
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Good but in general you need to complete your calculations and include units throughout.
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Solution
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