#$&* course MTH 279 4 4/8 Query 23 Differential Equations*********************************************
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Given Solution: &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary): OK ------------------------------------------------ Self-critique rating: OK ********************************************* Question: The equation y ' = [ y_2; y_3; -2 y_1 + 4 y_3 + e^(3 t) ] with initial condition y(0) = [1; -2; 3] represents a higher-order equation of form y[n] + a_(n-1) * y[n-1] + ... + a^2 y '' + a_1 y ' + a_0 y = g(t). (y[n], for example, represents the nth derivative of y; a_(n-1) is understood as a with subscript n - 1). What is the higher-order equation? YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your solution: y''' +2y - 4y'' = e^3t confidence rating #$&*: ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
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Given Solution: &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary): I noticed the y^n terms were out of order and missing a y_2 term, so I'm not sure if I interpreted the coefficient equations correctly or not. ------------------------------------------------ Self-critique rating: 3