cq_1_021

Phy 121

Your 'cq_1_02.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

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The problem:

A ball starts with velocity 4 cm/sec and ends with a velocity of 10 cm/sec.

What is your best guess about the ball's average velocity?

answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):

We don't know the exact distance traveled or how long that it took. I think that I remember reading that an object ended with normally double its average velocity

this is a special condition when acceleration is uniform and initial velocity is zero

so I'm thinking that the average would be 5 cm/sec. I guess another way is thinking about is by taking an average of the two numbers which would give us 7 cm/sec. So maybe a good answer will be between 5 and 7 cm/sec.

your reasoning on the 7 cm/s is correct

#$&*

Without further information, why is this just a guess?

answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):

This is a guess because we don't know the exact distance or time involved so we can't plug the numbers into the formula (change in distance over change in time).

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If it takes 3 seconds to get from the first velocity to the second, then what is your best guess about how far it traveled during

that time?

answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):

It takes 3 sec to go from 4 cm/sec to 10 cm/sec so 3 sec for a change in speed of 6 cm/sec.

With this in mind, I'm guessing that in 3 sec. it traveled 6 cm + 8cm + 10 cm= 24 cm

not quite; check the link given at the end

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At what average rate did its velocity change with respect to clock time during this interval?

answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):

It speeds up by 6 cm/sec in 3 sec. so I'm assuming that it is increasing its speed my 2 cm/sec each sec.

Very good.

#$&*

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15-20 min.

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2-3-10 at 6:45 p.m.

&#Please compare your solutions with the expanded discussion at the link

Solution

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