Phy 121
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The problem:
A ball accelerates at 8 cm/s^2 for 3 seconds, starting with velocity 12 cm/s.
What will be its velocity after the 3 seconds has elapsed?
answer/question/discussion: ->->->->->->->->->->->-> :
For every second it is accelerating an additional 8 cm/s which will mean that it will be at 12 cm/s + 3(8cm/s) = 36 cm/s.
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Assuming that acceleration is constant, what will be its average velocity during this interval?
answer/question/discussion: ->->->->->->->->->->->-> :
(36 cm/s + 12 cm/s)/2= 24 cm/s is the average velocity.
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How far will it travel during this interval?
answer/question/discussion: ->->->->->->->->->->->-> :
Average velocity=change in position/clock time
24 cm/s = change in position/3 sec
72 cm = change in position
#$&*
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Revised: 06 Feb 2010 17:05:43 -0500
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