course phy 121
2/27 at 6:00 p.m.
If the slope of a graph of the acceleration of a cart vs. the number of paper clips attached by a string and suspended over a pulley is ( 20 cm/s2) / clip, and if the slope of a graph of number of paper clips needed to maintain equilibrium vs. ramp slope is 47 clips / unit of ramp slope, then how many cm/s2 of acceleration should correspond to 1 unit of
ramp slope? If 52 clips are necessary to match the mass of the cart, then if we could apply this force to the cart without the extra mass of all those clips, what would be the
acceleration of the cart?
a= 20 cm/s^2/clip
slope = rise/run= 47 clips/unit of ramp slope
47 clips * 20 cm/s^2 = 940 cm/s^2 for 47 clips or per 1 unit of ramp slope
52 clips * 20 cm/s^2= 1040 cm/s^2 for 52 clips "
&#Very good work. Let me know if you have questions. &#