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PHY 201
Your 'cq_1_07.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_07.1_labelMessages **
A ball falls freely from rest at a height of 2 meters. Observations indicate that the ball reaches the ground in .64 seconds.
• Based on this information what is its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
Use the formula ‘ds=v_0*’dt + .5*a*’dt^2 solved for a and with v_0 = 0
A=(2*’ds)/(‘dt^2) = (2*2m)/(0.64s)^2 = 4m / 0.4096 s^2 = 9.76563 m/s^2 = 9.8 m/s^2
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• Is this consistent with an observation which concludes that a ball dropped from a height of 5 meters reaches the ground in 1.05 seconds?
answer/question/discussion: ->->->->->->->->->->->-> :
Same formula as above
A=(2*5m)/(1.05 s)^2 = 9.07029 m/s^2 = 9.1 m/s^2
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• Are these observations consistent with the accepted value of the acceleration of gravity, which is 9.8 m / s^2?
answer/question/discussion: ->->->->->->->->->->->-> :
The second problem is not consistent with the accepted value unless there was a lot of air resistance. But the first problem is very close.
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The second result could be consistent with the accepted value, if the instruments used to obtain that value are not particularly accurate.
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&#Your work looks good. See my notes. Let me know if you have any questions. &#