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PHY 201
Your 'cq_1_10.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_10.1_labelMessages **
A pendulum requires 2 seconds to complete a cycle, which consists of a complete back-and-forth oscillation (extreme point to equilibrium to opposite extreme point back to equilibrium and finally to the original extreme point). As long as the amplitude of the motion (the amplitude is the distance from the equilibrium position to the extreme point) is small compared to the length of the pendulum, the time required for a cycle is independent of the amplitude.
• How long does it take to get from one extreme point to the other, how long from an extreme point to equilibrium, and how long to go from extreme point to equilibrium to opposite extreme point and back to equilibrium?
answer/question/discussion: ->->->->->->->->->->->-> :
One extreme point to the other would be a half cycle so 1 second.
One extreme point to equilibrium would be half of half a cycle or one quarter cycle. 2*.25 = 0.5 second.
Extreme to extreme and back to equilibrium would be a half cycle plus half of a half cycle or three quarters of a cycle. 2*0.75 = 1.5 seconds
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• What reasonable assumption did you make to arrive at your answers?
answer/question/discussion: ->->->->->->->->->->->-> :
This assumes that speed is constant.
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Speed is clearly not constant, since the pendulum periodically comes to rest and reverses direction.
However it seems pretty clear that you mean the rhythm of the pendulum is constant, requiring the same time in either direction between extreme point and equilibrium.
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