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PHY 201
Your 'cq_1_11.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_11.1_labelMessages **
Answer the following based on Newton's Second Law:
• How much net force is required to accelerate a 12 kg mass at 3 m/s^2?
answer/question/discussion: ->->->->->->->->->->->-> :
F_net = m*a = 12 kg * 3 m/s^2 = 36 Newtons
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• What would be the acceleration of a 4 kg mass subject to a net force of 20 Newtons?
answer/question/discussion: ->->->->->->->->->->->-> :
f_net = m*a solved for a
a = f_net/m = 20 N / 4 kg = 5 m/s^2
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• If you exert a force of 20 Newtons on a 10-kg object and it accelerates in the direction of your force at 1.5 m/s^2, then how do you know there are other forces acting on the object besides your own?
answer/question/discussion: ->->->->->->->->->->->-> :
f_net = 10 kg * 1.5 m/s^2 = 15 Newtons, this is not equal to the force being exerted on the object so there are other forces on the object. Since it is more than the net force, they are acting in the opposite direction of the force being exerted.
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• What is the total of all those forces and in what direction does this total act?
answer/question/discussion: ->->->->->->->->->->->-> :
Answered above.
F_net = 15 N = 20 N + f_other
F_other = 15 N - 20 N = -5 N
This means it is in the opposite direction of the force being exerted, or against the motion of the object.
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5 minutes
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&#Very good responses. Let me know if you have questions. &#