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PHY 201
Your 'cq_1_12.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_12.1_labelMessages **
Masses of 5 kg and 6 kg are suspended from opposite sides of a light frictionless pulley and are released.
• What will be the net force on the 2-mass system and what will be the magnitude and direction of its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
f_net = (6 kg*9.8m/s^2) - (5 kg * 9.8 m/s^2) = 9.8 N
a=9.8N/11kg = 0.89 m/s^2 in the positive direction towards the 6kg mass
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• If you give the system a push so that at the instant of release the 5 kg object is descending at 1.8 meters / second, what will be the speed and direction of motion of the 5 kg mass 1 second later?
answer/question/discussion: ->->->->->->->->->->->-> :
v_0 = - 1.8 m/s
‘dt = (v_f-v_0)/a = (0 - -1.8 m/s)/(0.89 m/s^2) = 2.02 s > 1 so it is still moving in the direction of the 5kg mass at t=1s
V_f = -1.8 m/s + 0.89 m/s^2 * 1 s = -0.91 m/s
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• During the first second, are the velocity and acceleration of the system in the same direction or in opposite directions, and does the system slow down or speed up?
answer/question/discussion: ->->->->->->->->->->->-> :
Velocity is negative while acceleration is positive, with my solution. The two are opposites in the first second. The system slows down until t=2.02 s, then reverses direction.
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10 minutes
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&#Very good responses. Let me know if you have questions. &#