cq_1_041

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PHY 241

Your 'cq_1_04.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

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The problem:

A ball is moving at 10 cm/s when clock time is 4 seconds, and at 40 cm/s when clock time is 9 seconds.

• Sketch a v vs. t graph and represent these two events by the points (4 sec, 10 cm/s) and (9 s, 40 cm/s).

• Sketch a straight line segment between these points.

• What are the rise, run and slope of this segment?

answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):

the rise of this graph is 40m/s-10m/s = 30m/s

the run is 9s-4s=5s

slope is 30m/s/5s=6m/s^2

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• What is the area of the graph beneath this segment?

answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):

The area of this trapezoid is the average altitude * the base length. Average altitude is 40+10/2=50/2=25m/s

25m/s* 5sec = 125m this is the displacement in the time interval.

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5min

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&#Very good responses. Let me know if you have questions. &#