RandomProbAsst4

#$&*

course PHY 241

2/24 1

A bee is making a beeline for its hive. Its velocity is measured at a distance of 75 meters from the observer and again at distance 145 meters from the observer. The clock times at these two positions are t = 9 sec and t = 16 sec, and the measured velocities are 3 m/sec and 13.5 m/sec. What is its average velocity during this time? What is its average acceleration during this time? Is it possible that the acceleration is uniform?

`dt= 16s-9s=7s

`dv=13.5m/s-3m/s=10.5m/s

vAve=(13.5m/s+3m/s)/2=16.5m/s /2 =8.25m/s

@&
vAve is, by definition, equal to (change in position) / (change in clock time).

You have averaged the initial and final velocities. If acceleration is uniform this will give you the correct average velocity. If not, it's unlikely that it will.
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aAve=`dv/`dt=10.5m/s /7s=

=1.5m/s/s

If acceleration is uniform then the graph of velocity versus time will be a straight line.

It is possible but very unlikely that this acceleration is uniform. A bee would probably change acceleration due to wind changes.

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You need to answer this question based on the data.
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You haven't calculated the average velocity based on displacement and clock time. That value would trump the one you did calculate.

You also need to answer that last question based on the information given.
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@&

&#Please see my notes and submit a copy of this document with revisions, comments and/or questions, and mark your insertions with &&&& (please mark each insertion at the beginning and at the end).
Be sure to include the entire document, including my notes.

RandomProbAsst4

@& vAve is, by definition, equal to (change in position) / (change in clock time). You have averaged the initial and final velocities. If acceleration is uniform this will give you the correct average velocity. If not, it's unlikely that it will. *@

@& You need to answer this question based on the data. *@

@& You haven't calculated the average velocity based on displacement and clock time. That value would trump the one you did calculate. You also need to answer that last question based on the information given. *@

@&

&#Please see my notes and submit a copy of this document with revisions, comments and/or questions, and mark your insertions with &&&& (please mark each insertion at the beginning and at the end).Be sure to include the entire document, including my notes.

@&
vAve is, by definition, equal to (change in position) / (change in clock time).

You have averaged the initial and final velocities. If acceleration is uniform this will give you the correct average velocity. If not, it's unlikely that it will.
*@

@&
You need to answer this question based on the data.
*@

@&
You haven't calculated the average velocity based on displacement and clock time. That value would trump the one you did calculate.

You also need to answer that last question based on the information given.
*@

&#Please see my notes and submit a copy of this document with revisions, comments and/or questions, and mark your insertions with &&&& (please mark each insertion at the beginning and at the end).
Be sure to include the entire document, including my notes.