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course PHY 241

Situation 7:vf=10m/s

v0=?

'dt=5s

`ds=?

a=2m/s^2

Direct reasoning- after 5 seconds accelerating 2m/s^2 the change in velocity would be 10m/s. final velocity minus ‘dv would be 0m/s v0 would be 0m/s.

Now to find `ds displacement. Average velocity times time = displacement. Vave would be 10-0/2= 5m/s multiply by time of 5 s = 25m.

Equations:

vf = v0 + a * `dt

10m/s = v0 + 2m/s^2 * 5s

V0=0m/s

‘ds = (v0 + vf) / 2 * `dt

ds = (0 + 10) / 2 * 5s

ds = (0 + 10m/s) / 2 * 5s

`ds=25m