#$&*
course PHY 241
Situation 7:vf=10m/s
v0=?
'dt=5s
`ds=?
a=2m/s^2
Direct reasoning- after 5 seconds accelerating 2m/s^2 the change in velocity would be 10m/s. final velocity minus ‘dv would be 0m/s v0 would be 0m/s.
Now to find `ds displacement. Average velocity times time = displacement. Vave would be 10-0/2= 5m/s multiply by time of 5 s = 25m.
Equations:
vf = v0 + a * `dt
10m/s = v0 + 2m/s^2 * 5s
V0=0m/s
‘ds = (v0 + vf) / 2 * `dt
ds = (0 + 10) / 2 * 5s
ds = (0 + 10m/s) / 2 * 5s
`ds=25m
Good work. Let me know if you have questions.