week4quiz1

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course PHY 241

A projectile leaves the edge of a table and, while traveling horizontally at a constant 31 cm/s, falls freely a distance of 58 cm to the floor. If its vertical acceleration is 980 cm/s2, how long does it take to fall and how far does it travel in the horizontal direction during the fall?Vertical

vf=?

v0=0

'dt=?

`ds=58cm

a=980cm/s^2

vf^2 = v0^2 + 2 a `ds.

vf^2 = 0^2 + 2 (980cm/s^2)` *58cm

vf^2 = + 2 (980cm/s^2) *58cm

vf^2 = 113680m^2/s^2

vf = 337.16 cm/s

I didn’t really need to find vf but I did anyway.

`ds = v0 `dt + .5 a `dt^2

58cm = 0 `dt + .5 980cm/s^2 `dt^2

58cm = 490cm/s^2 `dt^2

`dt^2=0.12s^2

Dt=0.35s the object falls for .35 s

vf=31cm/s

v0=31cm/s

'dt=0.35s

`ds=?

a=0

vave will be 31cm/s for 0.35s ‘ds = vave*`dt=31cm/s*0.35s=10.85cm

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&#Very good responses. Let me know if you have questions. &#