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course PHY 241
A projectile leaves the edge of a table and, while traveling horizontally at a constant 31 cm/s, falls freely a distance of 58 cm to the floor. If its vertical acceleration is 980 cm/s2, how long does it take to fall and how far does it travel in the horizontal direction during the fall?Vertical
vf=?
v0=0
'dt=?
`ds=58cm
a=980cm/s^2
vf^2 = v0^2 + 2 a `ds.
vf^2 = 0^2 + 2 (980cm/s^2)` *58cm
vf^2 = + 2 (980cm/s^2) *58cm
vf^2 = 113680m^2/s^2
vf = 337.16 cm/s
I didn’t really need to find vf but I did anyway.
`ds = v0 `dt + .5 a `dt^2
58cm = 0 `dt + .5 980cm/s^2 `dt^2
58cm = 490cm/s^2 `dt^2
`dt^2=0.12s^2
Dt=0.35s the object falls for .35 s
vf=31cm/s
v0=31cm/s
'dt=0.35s
`ds=?
a=0
vave will be 31cm/s for 0.35s ‘ds = vave*`dt=31cm/s*0.35s=10.85cm
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&#Very good responses. Let me know if you have questions. &#