#$&* Phy 201
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The first one or two sounds seem like their are in constant rhythym, or equal spacing apart. After that the rhythym gets faster and faster and closer together until it's emits a hum for a second or two because they are so close together. In the beginning, when in constant rhythym, it may or may not actually be in constant rhythym, based on my ability to audibly and accurately detect it. #$&* If the bracket is tilted forward a bit, as shown in the figure below, the pearl will naturally hang away from the bracket. Tilt the bracket forward a little bit (not as much as shown in the figure, but enough that the pearl definitely hangs away from the bracket). Keep the bracket stationary and release the pendulum. Note whether the pearl strikes the bracket more and more frequently or less and less frequently with each bounce. Again listen to the rhythm of the sounds made by the ball striking the bracket. Do the sounds get closer together or further apart, or does the rhythm remain steady? I.e., does the rhythm get faster or slower, or does it remain constant? Repeat a few times if necessary until you are sure of your answer. Insert your answer into the box below, and give a good description of what you heard.your response &&&&&&&&&&&&&&&&&&
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The rhythym here is more constant (at least as far as I can audibly detect), but it does get get slower and further apart very gradually. So, it starts out loud and relatively constant, and very gradually gets slower and further apart until it's no longer bounding off the bracket. #$&* If the bracket is placed on a perfectly level surface, the pearl will hang straight down, just barely touching the bracket. However most surfaces on which you might place the bracket aren't perfectly level. Place the bracket on a smooth surface and if necessary tilt it a bit by placing a shim (for a shim you could for example use a thin coin, though on most surfaces you wouldn't need anything this thick; for a thinner shim you could use a tightly folded piece of paper) beneath one end or the other, adjusting the position and/or the thickness of the shim until the hanging pearl just barely touches the bracket. Pull the pearl back then release it. If the rhythm of the pearl bouncing off the bracket speeds up or slows down, adjust the level of the bracket, either tilting it a bit forward or a bit backward, until the rhythm becomes steady. Describe the process you used to make the rhythm steady, and describe just how steady the rhythm was, and how many times the pendulum hit the bracket..your response &&&&&&&&&&&&&&&&&&
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I tilted the bracket forward with a stack of 17 business cards at the end of the bracket. I had to move the stack of cards near the center of the bracket leg on the table to get it so the bead was barely touching the bracket and producing a fairly steady rhythm. Once done, it produced a steady rhythym for about 10 swings/hits. After that it slowed for the remaining 10 quiet swings/hits. #$&* On a reasonably level surface, place one domino under each of the top left and right corners of your closed textbook, with the front cover upward. Place the bracket pendulum on the middle of the book, with the base of the bracket parallel to one of the sides of the book. Release the pendulum and observe whether the sounds get further apart or closer together. Note the orientation of the bracket and whether the sounds get further apart or closer together. Now rotate the base of the bracket 45 degrees counterclockwise and repeat, being sure to note the orientation of the bracket and the progression of the sounds. Rotate another 45 degrees and repeat. Continue until you have rotated the bracket back to its original position. Report your results in such a way that another student could read them and duplicate your experiment exactly. Try to report neither more nor less information than necessary to accomplish this goal. Use a new line to report the results of each new rotation.your response &&&&&&&&&&&&&&&&&&
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Starting at 0 or 360 on the opposite side of the book where the dominoes were located, and moving counter clockwise every 45 degress, this is the behavior of the bead/pendulum at 0/360 degrees and every 45 degress thereafter. 0/360 (tilt is slightly forward): 6 or 7 fairly constant, steady hits before speeding up and getting closer together before stopping. 45: Same pattern as 0 degrees but slightly more constant, slower, and louder for first 6-7 hits before speeding up and stopping. 90 (tilt slightly backward): Fast but fairly constant for 8-9 hits before speeding up and stopping. 135 (tilt slightly backward): Same patten as 90 degrees but slightly slower. 180 (small back tilt): Fast the whole time. 2-3 fast constant hits before speeding up even faster before stopping. 225 (slight back tilt): Constant medium to fast speed for 8-9 hits before speeding up and stopping. 270 (nearly straight up and down/no tilt): Most constant (evenly spaced) so far, with speeding up and stopping only at very end (last 2-3 hits). 315 (nearly straight): Slow/medium speed and constant until last 4-6 hits until stopping. #$&* Describe how you would orient the bracket to obtain the most regular 'beat' of the pendulum.your response &&&&&&&&&&&&&&&&&&
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Although the straighter bracket yielded the most regular beat in the previous question, based on trials in other questions (and repeating a slightly forward bracket myself) the slightly forward tilt produced the most regular beat pattern. #$&* Orient the bracket in this position and start the TIMER program. Adjust the pendulum to the maximum length at which it will still bounce regularly. Practice the following procedure for a few minutes: Pull the pendulum back, ready to release it, and place your finger on the button of your mouse. Have the mouse cursor over the Click to Time Event button. Concentrate on releasing the pendulum at the same instant you click the mouse, and release both. Do this until you are sure you are consistently releasing the pendulum and clicking the mouse at the same time. Now you will repeat the same procedure, but you will time both the instant of release and the instant at which the pendulum 'hits' the bracket the second time. The order of events will be: click and release the pendulum simultaneously the pendulum will strike the bracket but you won't click the pendulum will strike the bracket a second time and you will click at the same instant We don't attempt to time the first 'hit', which occurs too soon after release for most people to time it accurately. Practice until you can release the pendulum with one mouse click, then click again at the same instant as the second strike of the pendulum. When you think you can conduct an accurate timing, initialize the timer and do it for real. Do a series of 8 trials, and record the 8 time intervals below, one interval to each line. You may round the time intervals to the nearest .001 second. Starting in the 9th line, briefly describe what your numbers mean and how they were obtained.your response &&&&&&&&&&&&&&&&&&
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.414 .648 .680 .664 .602 .578 .516 .555 The results were obtained by putting the bracket in the ideal position and inclide to get steady hits. The timer was clicked on release and every 2nd hit. Toward the end it began to get faster. #$&* Finally, you will repeat once more, but you will time every second 'hit' until the pendulum stops swinging. That is, you will release, time the second 'hit', then time the fourth, the sixth, etc.. Practice until you think you are timing the events accurately, then do four trials. Report your time intervals for each trial on a separate line, with commas between the intervals. For example look at the format shown below: .925, .887, .938, .911 .925, .879, .941 etc. In the example just given, the second trial only observed 3 intervals, while the first observed 4. This is possible. Just report what happens in the space below. Then on a new line give a brief description of what your results mean and how they were obtained.your response &&&&&&&&&&&&&&&&&&
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.703, .695, .688, .563, .570, .680, .641, .578, .468, .375 I recorded upon release of the pendulum and every second hit. These are the time intervals in seconds. #$&* Now measure the length of the pendulum. (For the two-pearl system the length is measured from the bottom of the 'fixed' pearl (the one glued to the top of the bracket) to the middle of the 'swinging' pearl. For the system which uses a bolt and magnet at the top instead of the pearl, you would measure from the bottom of the bolt to the center of the pearl). Using a ruler marked in centimeters, you should be able to find this length to within the nearest millimeter. What is the length of the pendulum?your response &&&&&&&&&&&&&&&&&&
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10.50 cm or 105 mm #$&* If you have timed these events accurately, you will see clearly that the time from release to the second 'hit' appears to be different than the time between the second 'hit' and the fourth 'hit'. On the average, how much time elapses between release and the second 'hit' of the pendulum, how much time elapses between the second and fourth 'hit' and how much time elapses between the fourth and sixth 'hit'? Report your results as three numbers separated by commas, e.g., .63, .97, .94your response &&&&&&&&&&&&&&&&&&
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.703, .695, .688 #$&* A full cycle of a free pendulum is from extreme point to equilibrium to opposite extreme point then back to equilibrium and finally back to the original extreme point (or almost to the original extreme point, since the pendulum is losing energy as it swings).. The pearl pendulum is released from an 'extreme point' and strikes the bracket at its equilibrium point, so it doesn't get to the opposite extreme point. It an interval consists of motion from extreme point to equilibrium, or from equilibrium to extreme point, how many intervals occur between release and the first 'hit'?your response &&&&&&&&&&&&&&&&&&
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If an interval is from extreme point to equilibrium (hit), then release and first hit would be 1 interval. #$&* How many intervals, as the word was described above, occur between the first 'hit' and the second 'hit'? Explain how your description differs from that of the motion between release and the first 'hit'.your response &&&&&&&&&&&&&&&&&&
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3 intervals #$&* How many intervals occur between release and the second 'hit', and how does this differ from the motion between the second 'hit' and the fourth 'hit'?your response &&&&&&&&&&&&&&&&&&
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3 intervals. Between 2nd and 4th hit is 4 intervals. #$&* How many intervals occur between the second 'hit' and the fourth 'hit', and how does this differ from a similar description of the motion between the fourth 'hit' and the sixth 'hit'?your response &&&&&&&&&&&&&&&&&&
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4 intervals. Both are 4 intervals. #$&* Why would we expect that the time interval between release to 2d 'hit' should be shorter than the subsequent timed intervals (2d to 4th, 4th to 6th, etc.)?your response &&&&&&&&&&&&&&&&&&
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Upon first release there was more energy, so it bounced faster. Energy decreased after that so the subsequant intervals shortened.your response &&&&&&&&&&&&&&&&&&
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Mine decreased because as it lost energy, the pendulum traveled shorter distances and sped up until in stopped. #$&* What evidence does this experiment provide for or against the hypothesis that the length of a pendulum's swing depends only on its length, and is independent of how far it actually swings?your response &&&&&&&&&&&&&&&&&&
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I'm not sure I understand. The length of the string determines how far it's possible to swing (I would think). However when I releases a pendulum of the same length for shorter and higher heights, the higher ones seemed to swing higher. #$&*your response &&&&&&&&&&&&&&&&&&
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A long time. The timer was difficult to master and my bead had a very short long end of string, which made it detach several times. #$&* *#&!Revision isn't requested, but if you do choose to submit revisions, clarifications or questions, please insert them into a copy of this document, and mark your insertions with &&&& (please mark each insertion at the beginning and at the end).
Be sure to include the entire document, including my notes.