cq_1_192

#$&*

PHY 241

Your 'cq_1_19.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

** CQ_1_19.2_labelMessages **

Sketch a vector representing a 10 Newton force which acts vertically downward.

• Position an x-y coordinate plane so that the initial point of your vector is at the origin, and the angle of the vector as measured counterclockwise from the positive x axis is 250 degrees. This will require that you 'rotate' the x-y coordinate plane from its traditional horizontal-vertical orientation.

answer/question/discussion: ->->->->->->->->->->->-> :

#$&*

• What are the x and y components of the equilibrant of the force?

answer/question/discussion: ->->->->->->->->->->->-> :

x=2.59N y=9.66N

#$&*

** **

1min

** **

@&

10 cos(250 deg) = -3.4 and 10 sin(theta) = -9.4, each to two significant figures.

You don't indicate how you got your results, but this is the way to do it.

*@

@&

The signs are essential.

*@