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PHY 241
Your 'cq_1_24.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_24.2_labelMessages **
A steel ball of mass 60 grams, moving at 80 cm / sec, collides with a stationary marble of mass 20 grams. As a result of the collision the steel ball slows to 50 cm / sec and the marble speeds up to 70 cm / sec.
Is the total momentum of the system after collision the same as the total momentum before?
answer/question/discussion: ->->->->->->->->->->->-> :
m1v1+m2v2=m1v1+m2v2
60g*80 cm/s +20g*0=60g*50 cm/s +20g*70 cm/s
60g*80 cm/s +20g*0=60g*50 cm/s +20g*70 cm/s
4800g cm/s=4400g cm/s
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What would the marble velocity have to be in order to exactly conserve momentum, assuming the steel ball's velocities to be accurate?
answer/question/discussion: ->->->->->->->->->->->-> :
60g*80 cm/s +20g*0=60g*50 cm/s +20g*v2
4800g cm/s=3000 g cm/s+20gv2
V2=90m/s
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5min
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Good responses. Let me know if you have questions.