Phy 231
Your 'cq_1_11.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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Answer the following based on Newton's Second Law:
• How much net force is required to accelerate a 12 kg mass at 3 m/s^2?
answer/question/discussion: ->->->->->->->->->->->-> :Fnet=ma
12kg*3m/s^2= 36 Newtons
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• What would be the acceleration of a 4 kg mass subject to a net force of 20 Newtons?
answer/question/discussion: ->->->->->->->->->->->-> :
Fnet=ma
a=Fnet/m
20newtons/ 4= 5m/s^2
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• If you exert a force of 20 Newtons on a 10-kg object and it accelerates in the direction of your force at 1.5 m/s^2, then how do you know there are other forces acting on the object besides your own?
answer/question/discussion: ->->->->->->->->->->->-> :
we know that the if there were no opposing forces then the net force would be 20newtons/10kg which would = 2m/s^2 so since the acceleration is 1.5m/s^2 then we know that there is another force in the other direction against the motion of the object and 20 Newton force.
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• What is the total of all those forces and in what direction does this total act?
answer/question/discussion: ->->->->->->->->->->->-> : we know that we have 20 Newton force in the motion of the object. We also know that since the acceleration is 1.5 instead of 2m/s^2 then the new force is 15 and that there is a force of 5 Newton in the opposite direction of the 20. So we have +20N and -5N
The net force direction is in that of the 20 Nforce.
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20min
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&#This looks very good. Let me know if you have any questions. &#