cq_1_072

phy 201

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An automobile rolls 10 meters down a constant incline with slope .05 in 8 seconds, starting from rest. The same automobile requires 5 seconds to roll the same distance down an incline with slope .10, again starting from rest.

• At what average rate is the automobile's acceleration changing with respect to the slope of the incline?

answer/question/discussion: ->->->->->->->->->->->-> :

v0= 0m/s

‘ds=10m

‘dt= 8seconds

`ds = (vf + v0) / 2 * `dt

10m= (vf+0)/2*8s

Vf=2.5

10/8= 1.25m/s

2.5/8= .313m/s^2 (acceleration)

Part 2: 10m/5s= 2m/s

`ds = (vf + v0) / 2 * `dt

10m=(vf+0)/2*5

Vf= 4m/s

4/5= 0.8m/s^2

.0.8-.313=.487m/s^2 difference in the two slopes

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20 minutes

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