phy 201
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An automobile rolls 10 meters down a constant incline with slope .05 in 8 seconds, starting from rest. The same automobile requires 5 seconds to roll the same distance down an incline with slope .10, again starting from rest.
• At what average rate is the automobile's acceleration changing with respect to the slope of the incline?
answer/question/discussion: ->->->->->->->->->->->-> :
v0= 0m/s
‘ds=10m
‘dt= 8seconds
`ds = (vf + v0) / 2 * `dt
10m= (vf+0)/2*8s
Vf=2.5
10/8= 1.25m/s
2.5/8= .313m/s^2 (acceleration)
Part 2: 10m/5s= 2m/s
`ds = (vf + v0) / 2 * `dt
10m=(vf+0)/2*5
Vf= 4m/s
4/5= 0.8m/s^2
.0.8-.313=.487m/s^2 difference in the two slopes
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20 minutes
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