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Phy 231
Your 'cq_1_27.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A ball of mass 400 grams is immersed in water. The ball is suspended in the water by a rubber band chain which exerts a tension force of 2.5 Newtons on the ball.
What is the weight of the ball?
answer/question/discussion: ->->->->->->->->->->->-> :
W = m * g
W = .4 kg * 9.8 m/s^2 = 3.92 N downward
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What is the buoyant force on the ball?
answer/question/discussion: ->->->->->->->->->->->-> :
The sum of the forces are 0 because it is in equilibrium.
0 = 2.5 - 3.92 + Fbuoy
Fbuoy = 1.42N
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What therefore must be its volume?
answer/question/discussion: ->->->->->->->->->->->-> :
The buoyant force is equal to the weight of the water it displaces, so the amount of water displaced must equal 1.42 N
V = 1.42N / 9800 N/m^3 = 1.45 * 10^-4 m^3
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What is its density?
answer/question/discussion: ->->->->->->->->->->->-> :
D = mass / volume
D = 400 / 1.45*10^-4 = 2758 * 10^-3 = 2800*10^-3 g/m^3
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&#Very good work. Let me know if you have questions. &#