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Phy 231
Your 'cq_1_24.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_24.2_labelMessages **
A steel ball of mass 60 grams, moving at 80 cm / sec, collides with a stationary marble of mass 20 grams. As a result of the collision the steel ball slows to 50 cm / sec and the marble speeds up to 70 cm / sec.
Is the total momentum of the system after collision the same as the total momentum before?
answer/question/discussion: ->->->->->->->->->->->-> :
The equation for the momentum of a mass is p = m * v
the inital momentum is: (.06 kg * 8 m/s) + (.02 kg * 0 m/s) = .048 kg m/s
the final momentum is: (.06 *.5 m/s) + (.02 * .7) = .044 kg* m/s
Therefore, the total momentum before the collision would be greater than the momentum after the collision.
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What would the marble velocity have to be in order to exactly conserve momentum, assuming the steel ball's velocities to be accurate?
answer/question/discussion: ->->->->->->->->->->->-> :
We know that the momentum of the steel ball was .048 before the collision and .03 after the collision.
Then, the momentum of the marble is .048 - .03 = .018 kg m/s
From there: .02kg * v = .018 which is .9 m/s
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35 min.
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