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course Phy 232
Starting with the cap in place on an empty bottle, siphon water from an adjacent full bottle. Allow the siphon to run a few minutes until the water levels in the two bottles stabilize. Estimate the percent change in the volume of the air in the capped bottle.
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%25
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Estimate the percent change in the number of molecules in the air within the capped bottle.
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Same number
0%
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Estimate the percent change in the volume of the water in the open bottle.
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half
50%
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What do you think is the percent change in the air pressure in the capped bottle?
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%25
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What is the difference in the two fluid levels?
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Same fluid levels
0%
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What is the percent change in the number of air molecules in the capped bottle?
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0%
Same number
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Raise the open bottle as high as possible without disturbing the capped bottle. Allow time for the water levels in the two bottles to stabilize.
What percent of the volume of the capped bottle do you now estimate is occupied by water?
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%50
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Estimate the percent change in the number of molecules in the air within the capped bottle.
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0% change
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By what percent do you estimate the pressure in the capped bottle exceeds the original pressure (i.e., the pressure when the bottle was first capped)?
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50%
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What percent of the uncapped bottle do you estimate is now occupied by air?
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75%
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What is the difference in the two water levels?
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Water level in the closed bottle is higher than the open one.
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Return the uncapped bottle to the tabletop. What happens?
What is now the difference in the two water levels?
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The water flows back into the capped bottle untill the water levels become equal.
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What do you think is the pressure in the uncapped bottle as a percent of its original pressure (before the bottle was capped)?
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I believe the water pressure will be similar to the original and have equal forces to the outside of the botttle.
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This looks good. Let me know if you have any questions.