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Phy 201
Your 'cq_1_02.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_02.1_labelMessages.txt **
The problem:
A ball starts with velocity 4 cm/sec and ends with a velocity of 10 cm/sec.
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What is your best guess about the ball's average velocity?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
10-4 = 6 meters per second
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That is the change in velocity, not the average velocity.
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Without further information, why is this just a guess?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
We do not know the change in clock time, so we do not know the actual velocity
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If it takes 3 seconds to get from the first velocity to the second, then what is your best guess about how far it traveled during that time?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
6 (cm/s) / 3 seconds= 2 cm
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If something moves at 6 cm/s, it moves further than 2 cm in a single second.
Also the units of (cm/s) / s would be cm / s^2, not cm. So this calculation cannot give you the answer to 'how far'.
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At what average rate did its velocity change with respect to clock time during this interval?
6 meters/ 3 seconds= 2 meters per second
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
6 meters/3 seconds= 2 meters per second
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Note that it's cm, not m.
6 cm/s / (3 s) is a good calculation for this question. However the units of the result, which do follow from the calculation, are not cm/s.
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*#&!
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You are doing a good job of explaining your calculations.
However some of your calculations are not appropriate to the questions they are answering, and you have some errors with units.
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Be sure to include the entire document, including my notes. &#
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