class 051005
Give the two basic points of the function y = f(x) = x. Answer the following, including a sketch for each:
The two basic points are (0, 0) and (1, 1).
Give the three basic points of y = f(x) = x^2. Answer the same questions as above for this function.
The three basic points are (-1, 1), (0, 0) and (1, 1).
A vertical stretch by factor -2 will take these points to (-1, -2), (0, 0) and (1, -2).
A vertical shift of +5 will take these points to (-1, 3), (0, 5) and (1, 3).
The function will be y = -2 f(x) + 5 = -2 x^2 + 5.
If f(x) = -.3 x + 2, then give expressions for each of the following, simplifying where possible:
f(a+b) = -.3 ( a + b) + 2, which might be expressed as -.3 a - .3 b + 2.
f(x2) - f(x1) = [ -.3 x2 + 2 ] - [-.3 x1 + 2 ] = -.3 x2 + 2 + .3 x1 - 2 = -.3 x2 + .3 x1 = -.3(x2 - x1).
f(x2) - f(x1) = -.3(x2 - x1), by the steps shown above.
So
( f(x2) - f(x1) ) / (x2 - x1) = -.3 (x2 - x1) / (x2 - x1) = -.3.