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Simple harmonic motion occurs when a constant mass is subjected to a linear
restoring force. The angular frequency of the simple harmonic motion is
omega = sqrt(k / m). This is the most fundamental thing you need to know
about simple harmonic motion. The second thing is to understand that simple
harmonic motion of amplitude A and angular frequency omeaga can be modeled
by a point moving around a reference circle of radius A at angular velocity
omega. At each clock time t that point has a radial vector r, a velocity
vector v and a centripetal acceleration vector a. If each of these vectors
is respectively projected on the x axis (i.e., just multiply the magnitude
of the vector by the cosine of its angle with the x direction) the result is
the position, velocity and acceleration of the simple harmonic oscillator at
that clock time. (It is also possible to project the vectors onto the y axis
to get a alternative model; in fact the vectors can be projected onto any
straight line through the origin to get a valid model for simple harmonic
motion with amplitude A and angular frequency omega).
Remember that the force constant k for a rubber band chain is the slope of
the tension force vs. length graph. For a rubber band chain the graph won't
really be linear, but for a small range of motion in the vicinity of some
equilibrium point it will be nearly linear, and k will be taken as the slope
of the best-fit line.
Hang a known weight from a rubber band chain and let it oscillate gently
while you count oscillations for 30 seconds (if you don't have anything of
known weight, use a measured amount of water in a suspended plastic bag (if
you fill a soft drink container with water, then divide the contents in
half, the amount should be about right).
Figure out the angular frequency (omega) of the oscillations and use the
angular frequency, along with the mass of the hanging weight, to determine
the force constant k.
Verify the force constant k directly by again suspending the original weight
at its equilibrium position. Add a known weight equal to to the suspended
weight, with the additional weight of roughly 1/10 to 1/4 of the original
weight and see how far the system now hangs below the previous equilbrium
position. See if your result is consistent with your previously calculated
value of k.