questions 050921

My question is, on my quiz yesterday I did not read correctly and drew a graph of force vs. position insted of force vs. pullback like you wanted. But was that the correct fromat for the graph?, even though it was not what you asked for.

<h3>A force vs. position graph would be fine.

A force vs. pullback graph will be increasing.

If an object is being accelerated in the positive direction by a rubber band as the band snaps back, then the force vs. position graph will be decreasing. Its shape will be the reverse of the force vs. pullback graph.</h3>

I know that acceleration is equal to slope. or in other words rise divided by run or the average rate of change of velocity with respect to clock time. When you ask if it is possible that the acceleration is uniform is that the same thing as asking if the slope is always equal? How do you proof this.

<h3>Remember that vAve = `ds / `dt, and this is so whether acceleration is constant or not.

If acceleration is uniform, then the v vs. t graph is a straight line, and over any interval we have vAve = (vf + v0) / 2.

So if vAve is not equal to (vf + v0) / 2, then acceleration cannot be uniform.</h3>

<h3>If we know the time down the incline and the length of the incline, we can immediately find the average velocity on the incline.

If initial velocity is zero and we have the average velocity we can find the change in velocity.

If we know the change in velocity and the change in clock time we can find the acceleration.

This is what you need to do for every trial. You are given the time required for each of three trials, and you are given the length of the incline. So you can find the acceleration for each trial.

If a cart accelerates uniformly down an incline 78 cm long in 2.7 seconds, then we know that v0 = 0, `ds = 78 cm and `dt = 2.7 seconds. We could use the equations of motion to find a.

I know that acceleration is equal to slope. or in other words rise divided by run or the average rate of change of velocity
with respect to clock time. When you ask if it is possible that the acceleration is uniform is that the same thing as asking
if the slope is always equal? How do you proof this.

<h3>Remember that vAve = `ds / `dt, and this is so whether acceleration is constant or not.

If acceleration is uniform, then the v vs. t graph is a straight line, and over any interval we have vAve = (vf + v0) / 2.

So if vAve is not equal to (vf + v0) / 2, then acceleration cannot be uniform.</h3>