Give me proof that a longer pendulum requires more time to complete a cycle.

Find the frequency of your pendulum in cycles per minute (i.e., if it was swung for a full minute how many cycles would you observe?).

Find the period of your pendulum in seconds (i.e., how many seconds for a full swing?).

If I travel 300 miles in 6 hours then what is my average speed in miles / hour?

1.  .01667

2. 300

3.  50

4.  5

If I make $1000 in 10 hours then the rate at which I'm being paid, in dollars per hour, is

1.  10

2. 100

3. 1000

4. 10,000

If a pendulum swings 40 times in 70 seconds then the period of the pendulum, in seconds, is

1.  1.75

2. .37

3. 70

4. 40

5. not stated

If we divide 70 seconds by 40 swings we get

• 70 seconds / (40 swings) = 1.75 seconds / swing

T = .2 sqrt(L)

T is period in seconds, L is length in cm

length, period in seconds, frequency in cycles / minute

calculation of T = .2 sqrt(L)

University Physics question:

At what average rate does period change with respect to pendulum length between lengths of 15 cm and 20 cm?

If you got an observed period of .82 seconds and a calculated period of .78 seconds, then what is the discrepancy between the two?

1. .80 seconds

2. 1.60 seconds

3. .04 seconds

4. .02 seconds

What is the discrepancy as a percent of the calculated period?

1.  4%

2.  2%

3.  96%

4. 5%

5.  not given

... i.e., what is .04 seconds as a percent of .78 seconds?

.04 sec / (.78 sec) = .05, approx., or 5%.